1-2y+3y^2=y^2-2y+1

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Solution for 1-2y+3y^2=y^2-2y+1 equation: 



1-2y+3y^2=y^2-2y+1

We move all terms to the left:

1-2y+3y^2-(y^2-2y+1)=0

We get rid of parentheses

3y^2-y^2-2y+2y-1+1=0

We add all the numbers together, and all the variables

2y^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{4}=0$

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